[tex]diketahui \\ r 1= 16 \div 2 = 8 \\ r2 = 8 \div 2 = 4 \\ \\ luas \: lingkaran \\ \pi \times r \times r \\ \\ perbandingan \: luas \: lingkaran\\( \pi \times 8 \times 8) \div (\pi \times 4 \times 4) \\ 64 \div 16 \\ 4 \div 1[/tex]
[tex] \large{ \colorbox{lavender}{ \purple{ \boxed{ \green{ \star{ \purple{ \rm{«Penyelesaian \: Soal» : { \green{ \star}}}}}}}}}}[/tex]
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[tex]\huge{ \purple{ \mathfrak{♡Pembahasan♡ :}}} [/tex]
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- Diketahui :
diameter lingkaran A = 16 cm
jari-jari lingkaran A = [tex]\sf{\frac{d}{2}\frac{16~cm}{2} }[/tex] = 8 cm
Diameter Lingkaran B = 8 cm
Jari-jari Lingkaran B = [tex]\sf{\frac{d}{2} = \frac{8~cm}{2}}[/tex] = 4 cm
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- Ditanya :
perbandingan Luas lingkaran =... : ...
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- Jawab :
[tex]\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{c}\rm \underline{ \blue{perbandingan \: luas \: lingkaran : }} \\ \\ \sf{ = a : b = (\pi \times r \times r) :(\pi \times r \times r) } \\ \\ \sf{ = (3.14 \times 8\times 8) : (3.14 \times 4\times 4)} \\ \\ \sf{ = (314 \times 64) :(3.14 \times 16) } \\ \\ \sf{ = {200.69 \: cm}^{2} : {50.24 \: cm}^{2} } \\ \\ \sf{ = ( {200.69 \: cm}^{2} \div {50.24 \: cm)}^{2} : ( {50.24 \: cm}^{2} \div {50.24 \: cm}^{2}) } \\ \\ \underline{ \boxed{ \red{ \sf{ =4 : 1}}}}\end{array}}}\end{gathered} \end{gathered} [/tex]
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- Kesimpulan :
perbandingan luas lingkaran adalah : [tex]\underline{\boxed{\red{\rm{4:1}}}}[/tex]
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[tex] \colorbox{black}{ \blue{ \boxed{ \boxed{ \rm{@AvrilKim}}}}}[/tex]
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